Scope, or the set of rules that determine where your variables live, is one of the most basic concepts of any programming language. It's so fundamental, in fact, that it's easy to forget how subtle the rules can be!
Understanding exactly how the JavaScript engine "thinks" about scope will keep you from writing the common bugs that hoisting can cause, prepare you to wrap your head around closures, and get you that much closer to never writing bugs ever again.
... Well, it'll help you understand hoisting and closures, anyway.
In this article, we'll take a look at:
let
and const
change the gameLet's dive in.
If you've written even a line of JavaScript before, you'll know that where you define your variables determines where you can use them. The fact that a variable's visibility depends on the structure of your source code is called lexical scope.
There are three ways to create scope in JavaScript:
let
or const
inside a code block. Such declarations are only visible inside the block.catch
block. Believe it or not, this actually does create a new scope!"use strict"; var mr_global = "Mr Global"; function foo () { var mrs_local = "Mrs Local"; console.log("I can see " + mr_global + " and " + mrs_local + "."); function bar () { console.log("I can also see " + mr_global + " and " + mrs_local + "."); } } foo(); // Works as expected try { console.log("But /I/ can't see " + mrs_local + "."); } catch (err) { console.log("You just got a " + err + "."); } { let foo = "foo"; const bar = "bar"; console.log("I can use " + foo + bar + " in its block..."); } try { console.log("But not outside of it."); } catch (err) { console.log("You just got another " + err + "."); } // Throws ReferenceError! console.log("Note that " + err + " doesn't exist outside of 'catch'!")
The snippet above demonstrates all three scope mechanisms. You can run it in Node or Firefox, but Chrome doesn't play nice with let
, yet.
We'll talk about each of these in exquisite detail. Let's start with a detailed look at how JavaScript figures out what variables belong to what scope.
When you run a piece of JavaScript, two things happen to make it work.
During the compilation step, the JavaScript engine:
It's only during execution that the JavaScript engine actually sets the value of variable references equal to their assignment values. Until then, they're undefined
.
// I can use first_name anywhere in this program var first_name = "Peleke"; function popup (first_name) { // I can only use last_name inside of this function var last_name = "Sengstacke"; alert(first_name + ' ' + last_name); } popup(first_name);
Let's step through what the compiler does.
First, it reads the line var first_name = "Peleke"
. Next, it determines what scope to save the variable to. Because we're at the top level of the script, it realizes we're in the global scope. Then, it saves the variable first_name
to the global scope and initializes its value to undefined
.
Second, the compiler reads the line with function popup (first_name)
. Because the function keyword is the first thing on the line, it creates a new scope for the function, registers the function's definition to the global scope, and peeks inside to find variable declarations.
Sure enough, the compiler finds one. Since we have var last_name = "Sengstacke"
in the first line of our function, the compiler saves the variable last_name
to the scope of popup
—not to the global scope—and sets its value to undefined
.
Since there are no more variable declarations inside the function, the compiler steps back into the global scope. And since there are no more variable declarations there, this phase is done.
Note that we haven't actually run anything yet. The compiler's job at this point is just to make sure it knows everyone's name; it doesn't care what they do.
At this point, our program knows that:
first_name
in the global scope.popup
in the global scope.last_name
in the scope of popup
.first_name
and last_name
are undefined
.It doesn't care that we've assigned those variables values elsewhere in our code. The engine takes care of that in execution.
During the next step, the engine reads our code again, but this time, executes it.
First, it reads the line, var first_name = "Peleke"
. To do this, the engine looks up the variable called first_name
. Since the compiler has already registered a variable by that name, the engine finds it, and sets its value to "Peleke"
.
Next, it reads the line, function popup (first_name)
. Since we're not executing the function here, the engine isn't interested and skips on over it.
Finally, it reads the line popup(first_name)
. Since we are executing a function here, the engine:
popup
first_name
popup
as a function, passing the value of first_name
as a parameterWhen it executes popup
, it goes through this same process, but this time inside the function popup
. It:
last_name
last_name
's value equal to "Sengstacke"
alert
, executing it as a function with "Peleke Sengstacke"
as its parameterTurns out there's a lot more going on under the hood than we might have thought!
Now that you understand how JavaScript reads and runs the code you write, we're ready to tackle something a little closer to home: how hoisting works.
Let's start with some code.
bar(); function bar () { if (!foo) { alert(foo + "? This is strange..."); } var foo = "bar"; } broken(); // TypeError! var broken = function () { alert("This alert won't show up!"); }
If you run this code, you'll notice three things:
foo
before you assign to it, but its value is undefined
.broken
before you define it, but you'll get a TypeError
.bar
before you define it, and it works as desired.Hoisting refers to the fact that JavaScript makes all of our declared variable names available everywhere in their scopes—including before we assign to them.
The three cases in the snippet are the three you'll need to be aware of in your own code, so we'll step through each of them one by one.
Remember, when the JavaScript compiler reads a line like var foo = "bar"
, it:
foo
to the nearest scopefoo
to undefinedThe reason we can use foo
before we assign to it is because, when the engine looks up the variable with that name, it does exist. This is why it doesn't throw a ReferenceError
.
Instead, it gets the value undefined
, and tries to use that to do whatever you asked of it. Usually, that's a bug.
Keeping that in mind, we might imagine that what JavaScript sees in our function bar
is more like this:
function bar () { var foo; // undefined if (!foo) { // !undefined is true, so alert alert(foo + "? This is strange..."); } foo = "bar"; }
This is the First Rule of Hoisting, if you will: Variables are available throughout their scope, but have the value undefined
until your code assigns to them.
A common JavaScript idiom is to write all of your var
declarations at the top of their scope, instead of where you first use them. To paraphrase Doug Crockford, this helps your code read more like it runs.
When you think about it, that makes sense. It's pretty clear why bar
behaves the way that it does when we write our code the way JavaScript reads it, isn't it? So why not just write like that all the time?
The fact that we got a TypeError
when we tried to execute broken
before we defined it is just a special case of the First Rule of Hoisting.
We defined a variable, called broken
, which the compiler registers in the global scope and sets equal to undefined
. When we try to run it, the engine looks up the value of broken
, finds that it's undefined
, and tries to execute undefined
as a function.
Obviously, undefined
isn't a function—that's why we get a TypeError
!
Finally, recall that we were able to call bar
before we defined it. This is due to the Second Rule of Hoisting: When the JavaScript compiler finds a function declaration, it makes both its name and definition available at the top of its scope. Rewriting our code yet again:
function bar () { if (!foo) { alert(foo + "? This is strange..."); } var foo = "bar"; } var broken; // undefined bar(); // bar is already defined, executes fine broken(); // Can't execute undefined! broken = function () { alert("This alert won't show up!"); }
Again, it makes much more sense when you write as JavaScript reads, don't you think?
To review:
undefined
until assignment.Now let's take a look at two new tools that work a bit differently: let
and const
.
let
, const
, & the Temporal Dead ZoneUnlike var
declarations, variables declared with let
and const
don't get hoisted by the compiler.
At least, not exactly.
Remember how we were able to call broken
, but got a TypeError
because we tried to execute undefined
? If we'd defined broken
with let
, we'd have gotten a ReferenceError
, instead:
"use strict"; // You have to "use strict" to try this in Node broken(); // ReferenceError! let broken = function () { alert("This alert won't show up!"); }
When the JavaScript compiler registers variables to their scopes in its first pass, it treats let
and const
differently than it does var
.
When it finds a var
declaration, we register the name of the variable to its scope and immediately initialize its value to undefined
.
With let
, however, the compiler does register the variable to its scope, but does not initialize its value to undefined
. Instead, it leaves the variable uninitialized, until the engine executes your assignment statement. Accessing the value of an uninitialized variable throws a ReferenceError
, which explains why the snippet above throws when we run it.
The space between the beginning of top of the scope of a let
declaration and the assignment statement is called the Temporal Dead Zone. The name comes from the fact that, even though the engine knows about a variable called foo
at the top of the scope of bar
, the variable is "dead", because it doesn't have a value.
... Also because it'll kill your program if you try to use it early.
The const
keyword works the same way as let
, with two key differences:
const
.const
.This guarantees that const
will always have the value that you initially assigned to it.
// This is legal const React = require('react'); // This is totally not legal const crypto; crypto = require('crypto');
let
and const
are different from var
in one other way: the size of their scopes.
When you declare a variable with var
, it's visible as high up on the scope chain as possible—typically, at the top of the nearest function declaration, or in the global scope, if you declare it in the top level.
When you declare a variable with let
or const
, however, it's visible as locally as possible—only within the nearest block.
A block is a section of code set off by curly braces, as you see with if
/else
blocks, for
loops, and in explicitly "blocked" chunks of code, like in this snippet.
"use strict"; { let foo = "foo"; if (foo) { const bar = "bar"; var foobar = foo + bar; console.log("I can see " + bar + " in this bloc."); } try { console.log("I can see " + foo + " in this block, but not " + bar + "."); } catch (err) { console.log("You got a " + err + "."); } } try { console.log( foo + bar ); // Throws because of 'foo', but both are undefined } catch (err) { console.log( "You just got a " + err + "."); } console.log( foobar ); // Works fine
If you declare a variable with const
or let
inside a block, it's only visible inside the block, and only after you've assigned it.
A variable declared with var
, however, is visible as far away as possible—in this case, in the global scope.
If you're interested in the nitty-gritty details of let
and const
, check out what Dr Rauschmayer has to say about them in Exploring ES6: Variables and Scoping, and take a look at the MDN documentation on them.
this
& Arrow FunctionsOn the surface, this
doesn't seem to have a whole lot to do with scope. And, in fact, JavaScript does not resolve the meaning of this
according to the rules of scope we've talked about here.
At least, not usually. JavaScript, notoriously, does not resolve the meaning of the this
keyword based on where you used it:
var foo = { name: 'Foo', languages: ['Spanish', 'French', 'Italian'], speak : function speak () { this.languages.forEach(function(language) { console.log(this.name + " speaks " + language + "."); }) } }; foo.speak();
Most of us would expect this
to mean foo
inside the forEach
loop, because that's what it meant right outside it. In other words, we'd expect JavaScript to resolve the meaning of this
lexically.
But it doesn't.
Instead, it creates a new this
inside every function you define, and decides what it means based on how you call the function—not where you defined it.
That first point is similar to the case of redefining any variable in a child scope:
function foo () { var bar = "bar"; function baz () { // Reusing variable names like this is called "shadowing" var bar = "BAR"; console.log(bar); // BAR } baz(); } foo(); // BAR
Replace bar
with this
, and the whole thing should clear up instantly!
Traditionally, getting this
to work as we expect plain old lexically-scoped variables to work requires one of two workarounds:
var foo = { name: 'Foo', languages: ['Spanish', 'French', 'Italian'], speak_self : function speak_s () { var self = this; self.languages.forEach(function(language) { console.log(self.name + " speaks " + language + "."); }) }, speak_bound : function speak_b () { this.languages.forEach(function(language) { console.log(this.name + " speaks " + language + "."); }.bind(foo)); // More commonly:.bind(this); } };
In speak_self
, we save the meaning of this
to the variable self
, and use that variable to get the reference we want. In speak_bound
, we use bind
to permanently point this
to a given object.
ES2015 brings us a new alternative: arrow functions.
Unlike "normal" functions, arrow functions do not shadow their parent scope's this
value by setting their own. Rather, they resolve its meaning lexically.
In other words, if you use this
in an arrow function, JavaScript looks up its value as it would any other variable.
First, it checks the local scope for a this
value. Since arrow functions don't set one, it won't find one. Next, it checks the parent scope for a this
value. If it finds one, it'll use that, instead.
This lets us rewrite the code above like this:
var foo = { name: 'Foo', languages: ['Spanish', 'French', 'Italian'], speak : function speak () { this.languages.forEach((language) => { console.log(this.name + " speaks " + language + "."); }) } };
If you want more details on arrow functions, take a look at Envato Tuts+ Instructor Dan Wellman's excellent course on JavaScript ES6 Fundamentals, as well as the MDN documentation on arrow functions.
We've covered a lot of ground so far! In this article, you've learned that:
let
or const
before assignment throws a ReferenceError
, and that such variables are scoped to the nearest block.this
, and bypass traditional dynamic binding.You've also seen the two rules of hoisting:
var
declarations are available throughout the scopes where they're defined, but have the value undefined
until your assignment statements execute.A good next step is to use your newfangled knowledge of JavaScript's scopes to wrap your head around closures. For that, check out Kyle Simpson's Scopes & Closures.
Finally, there's a whole lot more to say about this
than I was able to cover here. If the keyword still seems like so much black magic, take a look at this & Object Prototypes to get your head around it.
In the meantime, take what you've learned and go write fewer bugs!
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waly Good blog post. I absolutely love this…